Base | Representation |
---|---|
bin | 1001101101100010111010… |
… | …10111000110111100101010 |
3 | 2210121121221101011011221120 |
4 | 10312301131113012330222 |
5 | 10244344340244001240 |
6 | 113230513232520110 |
7 | 4332634102410531 |
oct | 466613527067452 |
9 | 83547841134846 |
10 | 21356143734570 |
11 | 68940a9425a67 |
12 | 248ab693b0036 |
13 | bbbb4cc30a98 |
14 | 53b90007d318 |
15 | 2707c7bcbad0 |
hex | 136c5d5c6f2a |
21356143734570 has 16 divisors (see below), whose sum is σ = 51254744963040. Its totient is φ = 5694971662544.
The previous prime is 21356143734553. The next prime is 21356143734577. The reversal of 21356143734570 is 7543734165312.
It is a super-2 number, since 2×213561437345702 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (21356143734577) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 355935728880 + ... + 355935728939.
It is an arithmetic number, because the mean of its divisors is an integer number (3203421560190).
Almost surely, 221356143734570 is an apocalyptic number.
21356143734570 is an abundant number, since it is smaller than the sum of its proper divisors (29898601228470).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21356143734570 is a wasteful number, since it uses less digits than its factorization.
21356143734570 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 711871457829.
The product of its (nonzero) digits is 6350400, while the sum is 51.
Adding to 21356143734570 its reverse (7543734165312), we get a palindrome (28899877899882).
The spelling of 21356143734570 in words is "twenty-one trillion, three hundred fifty-six billion, one hundred forty-three million, seven hundred thirty-four thousand, five hundred seventy".
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