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2135666121447 = 33746411900189
BaseRepresentation
bin11111000100111111100…
…111101101101011100111
321120011112020120212222210
4133010333213231223213
5234442321011341242
64313040024454503
7310203540336645
oct37047747555347
97504466525883
102135666121447
11753804937911
122a5aa631a433
131265142a4691
147551c696195
153a8484c6d9c
hex1f13f9edae7

2135666121447 has 8 divisors (see below), whose sum is σ = 2847563927920. Its totient is φ = 1423772864640.

The previous prime is 2135666121439. The next prime is 2135666121499. The reversal of 2135666121447 is 7441216665312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2135666121447 - 23 = 2135666121439 is a prime.

It is a super-2 number, since 2×21356661214472 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2135666121396 and 2135666121405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2135666121047) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173829 + ... + 2074017.

It is an arithmetic number, because the mean of its divisors is an integer number (355945490990).

Almost surely, 22135666121447 is an apocalyptic number.

2135666121447 is a deficient number, since it is larger than the sum of its proper divisors (711897806473).

2135666121447 is a wasteful number, since it uses less digits than its factorization.

2135666121447 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2274833.

The product of its digits is 1451520, while the sum is 48.

The spelling of 2135666121447 in words is "two trillion, one hundred thirty-five billion, six hundred sixty-six million, one hundred twenty-one thousand, four hundred forty-seven".

Divisors: 1 3 374641 1123923 1900189 5700567 711888707149 2135666121447