Base | Representation |
---|---|
bin | 1001101110000011100001… |
… | …10101100001100011010011 |
3 | 2210200022010102221002112212 |
4 | 10313001300311201203103 |
5 | 10300141213442003042 |
6 | 113242530332142335 |
7 | 4334123660214563 |
oct | 467016065414323 |
9 | 83608112832485 |
10 | 21373650344147 |
11 | 68a0572455942 |
12 | 24924343079ab |
13 | bc06acb8186a |
14 | 53c6c1154da3 |
15 | 270e9eac5482 |
hex | 137070d618d3 |
21373650344147 has 2 divisors, whose sum is σ = 21373650344148. Its totient is φ = 21373650344146.
The previous prime is 21373650344119. The next prime is 21373650344191. The reversal of 21373650344147 is 74144305637312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21373650344147 - 230 = 21372576602323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21373650344095 and 21373650344104.
It is not a weakly prime, because it can be changed into another prime (21373650343147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10686825172073 + 10686825172074.
It is an arithmetic number, because the mean of its divisors is an integer number (10686825172074).
Almost surely, 221373650344147 is an apocalyptic number.
21373650344147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21373650344147 is an equidigital number, since it uses as much as digits as its factorization.
21373650344147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5080320, while the sum is 50.
The spelling of 21373650344147 in words is "twenty-one trillion, three hundred seventy-three billion, six hundred fifty million, three hundred forty-four thousand, one hundred forty-seven".
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