Base | Representation |
---|---|
bin | 1001101110000011100001… |
… | …10101100001100010110111 |
3 | 2210200022010102221002111211 |
4 | 10313001300311201202313 |
5 | 10300141213442002434 |
6 | 113242530332142251 |
7 | 4334123660214523 |
oct | 467016065414267 |
9 | 83608112832454 |
10 | 21373650344119 |
11 | 68a0572455917 |
12 | 2492434307987 |
13 | bc06acb81848 |
14 | 53c6c1154d83 |
15 | 270e9eac5464 |
hex | 137070d618b7 |
21373650344119 has 2 divisors, whose sum is σ = 21373650344120. Its totient is φ = 21373650344118.
The previous prime is 21373650344077. The next prime is 21373650344147. The reversal of 21373650344119 is 91144305637312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21373650344119 - 221 = 21373648246967 is a prime.
It is a super-2 number, since 2×213736503441192 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21373653344119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10686825172059 + 10686825172060.
It is an arithmetic number, because the mean of its divisors is an integer number (10686825172060).
Almost surely, 221373650344119 is an apocalyptic number.
21373650344119 is a deficient number, since it is larger than the sum of its proper divisors (1).
21373650344119 is an equidigital number, since it uses as much as digits as its factorization.
21373650344119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 21373650344119 in words is "twenty-one trillion, three hundred seventy-three billion, six hundred fifty million, three hundred forty-four thousand, one hundred nineteen".
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