Base | Representation |
---|---|
bin | 11111001001000100000… |
… | …110011000000001010001 |
3 | 21120120210210201200021002 |
4 | 133021010012120001101 |
5 | 240030243234012340 |
6 | 4315041415311345 |
7 | 310420043602541 |
oct | 37110406300121 |
9 | 7516723650232 |
10 | 2140036235345 |
11 | 755647734098 |
12 | 2a690597b555 |
13 | 126a5c7a24a8 |
14 | 75814c31321 |
15 | 3aa01eaa715 |
hex | 1f244198051 |
2140036235345 has 4 divisors (see below), whose sum is σ = 2568043482420. Its totient is φ = 1712028988272.
The previous prime is 2140036235329. The next prime is 2140036235369. The reversal of 2140036235345 is 5435326300412.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 876992917441 + 1263043317904 = 936479^2 + 1123852^2 .
It is a cyclic number.
It is not a de Polignac number, because 2140036235345 - 24 = 2140036235329 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2140036235299 and 2140036235308.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214003623530 + ... + 214003623539.
It is an arithmetic number, because the mean of its divisors is an integer number (642010870605).
Almost surely, 22140036235345 is an apocalyptic number.
It is an amenable number.
2140036235345 is a deficient number, since it is larger than the sum of its proper divisors (428007247075).
2140036235345 is an equidigital number, since it uses as much as digits as its factorization.
2140036235345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 428007247074.
The product of its (nonzero) digits is 259200, while the sum is 38.
The spelling of 2140036235345 in words is "two trillion, one hundred forty billion, thirty-six million, two hundred thirty-five thousand, three hundred forty-five".
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