Base | Representation |
---|---|
bin | 11111001001000100100… |
… | …100011011100101111101 |
3 | 21120120211100112222011021 |
4 | 133021010210123211331 |
5 | 240030302243124201 |
6 | 4315042300224141 |
7 | 310420200556342 |
oct | 37110444334575 |
9 | 7516740488137 |
10 | 2140044114301 |
11 | 755651125725 |
12 | 2a690853b051 |
13 | 126a613007b2 |
14 | 75815cc27c9 |
15 | 3aa02a14ea1 |
hex | 1f24491b97d |
2140044114301 has 2 divisors, whose sum is σ = 2140044114302. Its totient is φ = 2140044114300.
The previous prime is 2140044114223. The next prime is 2140044114323. The reversal of 2140044114301 is 1034114400412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2135473678276 + 4570436025 = 1461326^2 + 67605^2 .
It is a cyclic number.
It is not a de Polignac number, because 2140044114301 - 211 = 2140044112253 is a prime.
It is a super-2 number, since 2×21400441143012 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2140044114101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070022057150 + 1070022057151.
It is an arithmetic number, because the mean of its divisors is an integer number (1070022057151).
Almost surely, 22140044114301 is an apocalyptic number.
It is an amenable number.
2140044114301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140044114301 is an equidigital number, since it uses as much as digits as its factorization.
2140044114301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2140044114301 its reverse (1034114400412), we get a palindrome (3174158514713).
The spelling of 2140044114301 in words is "two trillion, one hundred forty billion, forty-four million, one hundred fourteen thousand, three hundred one".
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