2140121413 has 4 divisors (see below), whose sum is σ = 2140214080. Its totient is φ = 2140028748.

The previous prime is 2140121407. The next prime is 2140121447. The reversal of 2140121413 is 3141210412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 2140121413 - 2²⁵ = 2106566981 is a prime.

It is a super-2 number, since 2×2140121413² = 9160239324762233138, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140121713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19306 + ... + 68212.

It is an arithmetic number, because the mean of its divisors is an integer number (535053520).

Almost surely, 2^2140121413 is an apocalyptic number.

It is an amenable number.

2140121413 is a deficient number, since it is larger than the sum of its proper divisors (92667).

2140121413 is an equidigital number, since it uses as much as digits as its factorization.

2140121413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92666.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 2140121413 is about 46261.4462917017. The cubic root of 2140121413 is about 1288.6831127859.

Adding to 2140121413 its reverse (3141210412), we get a palindrome (5281331825).

The spelling of 2140121413 in words is "two billion, one hundred forty million, one hundred twenty-one thousand, four hundred thirteen".