Base | Representation |
---|---|
bin | 1100011101010000011… |
… | …1110111110101010101 |
3 | 202110101212202202211211 |
4 | 3013110013313311111 |
5 | 12001244112342442 |
6 | 242152120501421 |
7 | 21314264643265 |
oct | 3072407676525 |
9 | 673355682754 |
10 | 214012230997 |
11 | 828423637a4 |
12 | 3558831a871 |
13 | 17248321216 |
14 | a50305d7a5 |
15 | 58786c1617 |
hex | 31d41f7d55 |
214012230997 has 2 divisors, whose sum is σ = 214012230998. Its totient is φ = 214012230996.
The previous prime is 214012230973. The next prime is 214012231079. The reversal of 214012230997 is 799032210412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 207157881316 + 6854349681 = 455146^2 + 82791^2 .
It is a cyclic number.
It is not a de Polignac number, because 214012230997 - 219 = 214011706709 is a prime.
It is a super-2 number, since 2×2140122309972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214012230917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107006115498 + 107006115499.
It is an arithmetic number, because the mean of its divisors is an integer number (107006115499).
Almost surely, 2214012230997 is an apocalyptic number.
It is an amenable number.
214012230997 is a deficient number, since it is larger than the sum of its proper divisors (1).
214012230997 is an equidigital number, since it uses as much as digits as its factorization.
214012230997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 40.
The spelling of 214012230997 in words is "two hundred fourteen billion, twelve million, two hundred thirty thousand, nine hundred ninety-seven".
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