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214012231403 = 6710929304701
BaseRepresentation
bin1100011101010000011…
…1110111111011101011
3202110101212202210101212
43013110013313323223
512001244112401103
6242152120503335
721314264644415
oct3072407677353
9673355683355
10214012231403
1182842364033
123558831ab4b
1317248321469
14a50305d9b5
1558786c17d8
hex31d41f7eeb

214012231403 has 8 divisors (see below), whose sum is σ = 219199170960. Its totient is φ = 208883901600.

The previous prime is 214012231351. The next prime is 214012231453. The reversal of 214012231403 is 304132210412.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 214012231403 - 26 = 214012231339 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (214012231453) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14645048 + ... + 14659653.

It is an arithmetic number, because the mean of its divisors is an integer number (27399896370).

Almost surely, 2214012231403 is an apocalyptic number.

214012231403 is a deficient number, since it is larger than the sum of its proper divisors (5186939557).

214012231403 is a wasteful number, since it uses less digits than its factorization.

214012231403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29304877.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 214012231403 its reverse (304132210412), we get a palindrome (518144441815).

The spelling of 214012231403 in words is "two hundred fourteen billion, twelve million, two hundred thirty-one thousand, four hundred three".

Divisors: 1 67 109 7303 29304701 1963414967 3194212409 214012231403