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2140124423343 = 3713374807781
BaseRepresentation
bin11111001001001001010…
…110110010010010101111
321120121000221200002110020
4133021021112302102233
5240030433323021333
64315054245413223
7310422164310444
oct37111126622257
97517027602406
102140124423343
11755692498035
122a692b40a213
13126a74b3b73a
14758228299cb
153aa09aca3b3
hex1f2495b24af

2140124423343 has 4 divisors (see below), whose sum is σ = 2853499231128. Its totient is φ = 1426749615560.

The previous prime is 2140124423321. The next prime is 2140124423387. The reversal of 2140124423343 is 3433244210412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2140124423343 - 213 = 2140124415151 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140124423243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 356687403888 + ... + 356687403893.

It is an arithmetic number, because the mean of its divisors is an integer number (713374807782).

Almost surely, 22140124423343 is an apocalyptic number.

2140124423343 is a deficient number, since it is larger than the sum of its proper divisors (713374807785).

2140124423343 is an equidigital number, since it uses as much as digits as its factorization.

2140124423343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 713374807784.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 2140124423343 its reverse (3433244210412), we get a palindrome (5573368633755).

The spelling of 2140124423343 in words is "two trillion, one hundred forty billion, one hundred twenty-four million, four hundred twenty-three thousand, three hundred forty-three".

Divisors: 1 3 713374807781 2140124423343