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2140131214 = 213174147279
BaseRepresentation
bin111111110001111…
…1100111110001110
312112011000221010001
41333203330332032
513340333144324
6552210234514
7104014546414
oct17743747616
95464027101
102140131214
119a9059291
124b8885a3a
132814cc340
141643352b4
15c7d42e44
hex7f8fcf8e

2140131214 has 16 divisors (see below), whose sum is σ = 3459193920. Its totient is φ = 987164640.

The previous prime is 2140131211. The next prime is 2140131233. The reversal of 2140131214 is 4121310412.

It is a super-2 number, since 2×21401312142 = 9160323226274227592, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2140131191 and 2140131200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140131211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21627 + ... + 68905.

It is an arithmetic number, because the mean of its divisors is an integer number (216199620).

Almost surely, 22140131214 is an apocalyptic number.

2140131214 is a deficient number, since it is larger than the sum of its proper divisors (1319062706).

2140131214 is a wasteful number, since it uses less digits than its factorization.

2140131214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49035.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 2140131214 is about 46261.5522221207. The cubic root of 2140131214 is about 1288.6850800207.

Adding to 2140131214 its reverse (4121310412), we get a palindrome (6261441626).

The spelling of 2140131214 in words is "two billion, one hundred forty million, one hundred thirty-one thousand, two hundred fourteen".

Divisors: 1 2 13 26 1741 3482 22633 45266 47279 94558 614627 1229254 82312739 164625478 1070065607 2140131214