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21401314139969 is a prime number
BaseRepresentation
bin1001101110110111000011…
…01110100001111101000001
32210202221112101020112021022
410313123201232201331001
510301114342404434334
6113303343351235225
74336123341463541
oct467334156417501
983687471215238
1021401314139969
1169012789a0115
122497874978b15
13bc319b23690a
1453db871c9321
15271a6d57a82e
hex1376e1ba1f41

21401314139969 has 2 divisors, whose sum is σ = 21401314139970. Its totient is φ = 21401314139968.

The previous prime is 21401314139951. The next prime is 21401314140113. The reversal of 21401314139969 is 96993141310412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20345377042225 + 1055937097744 = 4510585^2 + 1027588^2 .

It is a cyclic number.

It is not a de Polignac number, because 21401314139969 - 240 = 20301802512193 is a prime.

It is a super-2 number, since 2×214013141399692 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21401314139969.

It is not a weakly prime, because it can be changed into another prime (21401314138969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700657069984 + 10700657069985.

It is an arithmetic number, because the mean of its divisors is an integer number (10700657069985).

Almost surely, 221401314139969 is an apocalyptic number.

It is an amenable number.

21401314139969 is a deficient number, since it is larger than the sum of its proper divisors (1).

21401314139969 is an equidigital number, since it uses as much as digits as its factorization.

21401314139969 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 21401314139969 in words is "twenty-one trillion, four hundred one billion, three hundred fourteen million, one hundred thirty-nine thousand, nine hundred sixty-nine".