21401314140113 has 2 divisors, whose sum is σ = 21401314140114. Its totient is φ = 21401314140112.

The previous prime is 21401314139969. The next prime is 21401314140133. The reversal of 21401314140113 is 31104141310412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15094872284944 + 6306441855169 = 3885212^2 + 2511263^2 .

It is a cyclic number.

It is not a de Polignac number, because 21401314140113 - 2⁸ = 21401314139857 is a prime.

It is not a weakly prime, because it can be changed into another prime (21401314140133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700657070056 + 10700657070057.

It is an arithmetic number, because the mean of its divisors is an integer number (10700657070057).

Almost surely, 2^{21401314140113} is an apocalyptic number.

It is an amenable number.

21401314140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21401314140113 is an equidigital number, since it uses as much as digits as its factorization.

21401314140113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 21401314140113 its reverse (31104141310412), we get a palindrome (52505455450525).

The spelling of 21401314140113 in words is "twenty-one trillion, four hundred one billion, three hundred fourteen million, one hundred forty thousand, one hundred thirteen".