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21401401440130 = 252140140144013
BaseRepresentation
bin1001101110110111001101…
…11011100011011110000010
32210202221202110111211120121
410313123212323203132002
510301120032232041010
6113303400150330454
74336125451513135
oct467334673433602
983687673454517
1021401401440130
1169013131a8008
12249789a059a2a
13bc31b3351a0a
1453db94a3221c
15271a760723da
hex1376e6ee3782

21401401440130 has 8 divisors (see below), whose sum is σ = 38522522592252. Its totient is φ = 8560560576048.

The previous prime is 21401401440127. The next prime is 21401401440163. The reversal of 21401401440130 is 3104410410412.

It can be written as a sum of positive squares in 2 ways, for example, as 20161833177249 + 1239568262881 = 4490193^2 + 1113359^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 21401401440095 and 21401401440104.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1070070071997 + ... + 1070070072016.

Almost surely, 221401401440130 is an apocalyptic number.

21401401440130 is a deficient number, since it is larger than the sum of its proper divisors (17121121152122).

21401401440130 is a wasteful number, since it uses less digits than its factorization.

21401401440130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2140140144020.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 21401401440130 its reverse (3104410410412), we get a palindrome (24505811850542).

The spelling of 21401401440130 in words is "twenty-one trillion, four hundred one billion, four hundred one million, four hundred forty thousand, one hundred thirty".

Divisors: 1 2 5 10 2140140144013 4280280288026 10700700720065 21401401440130