2140142313 has 8 divisors (see below), whose sum is σ = 2923121376. Its totient is φ = 1391962400.

The previous prime is 2140142309. The next prime is 2140142317. The reversal of 2140142313 is 3132410412.

It is an interprime number because it is at equal distance from previous prime (2140142309) and next prime (2140142317).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2140142313 - 2² = 2140142309 is a prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2140142313.

It is not an unprimeable number, because it can be changed into a prime (2140142317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8699643 + ... + 8699888.

It is an arithmetic number, because the mean of its divisors is an integer number (365390172).

Almost surely, 2^2140142313 is an apocalyptic number.

It is an amenable number.

2140142313 is a deficient number, since it is larger than the sum of its proper divisors (782979063).

2140142313 is a wasteful number, since it uses less digits than its factorization.

2140142313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17399575.

The product of its (nonzero) digits is 576, while the sum is 21.

The square root of 2140142313 is about 46261.6721811912. The cubic root of 2140142313 is about 1288.6873077799.

Adding to 2140142313 its reverse (3132410412), we get a palindrome (5272552725).

It can be divided in two parts, 2140 and 142313, that added together give a triangular number (144453 = T₅₃₇).

The spelling of 2140142313 in words is "two billion, one hundred forty million, one hundred forty-two thousand, three hundred thirteen".