Base | Representation |
---|---|
bin | 1100011101010011000… |
… | …1011111010001001111 |
3 | 202110102122022000202221 |
4 | 3013110301133101033 |
5 | 12001304410443211 |
6 | 242153150400211 |
7 | 21314456451232 |
oct | 3072461372117 |
9 | 673378260687 |
10 | 214023140431 |
11 | 82848535161 |
12 | 3558bb00067 |
13 | 1724a6709c9 |
14 | a50469d419 |
15 | 5879628c71 |
hex | 31d4c5f44f |
214023140431 has 2 divisors, whose sum is σ = 214023140432. Its totient is φ = 214023140430.
The previous prime is 214023140407. The next prime is 214023140489. The reversal of 214023140431 is 134041320412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214023140431 - 221 = 214021043279 is a prime.
It is a super-2 number, since 2×2140231404312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 214023140396 and 214023140405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214023140131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107011570215 + 107011570216.
It is an arithmetic number, because the mean of its divisors is an integer number (107011570216).
Almost surely, 2214023140431 is an apocalyptic number.
214023140431 is a deficient number, since it is larger than the sum of its proper divisors (1).
214023140431 is an equidigital number, since it uses as much as digits as its factorization.
214023140431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 214023140431 its reverse (134041320412), we get a palindrome (348064460843).
The spelling of 214023140431 in words is "two hundred fourteen billion, twenty-three million, one hundred forty thousand, four hundred thirty-one".
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