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214024121411 is a prime number
BaseRepresentation
bin1100011101010011010…
…1001110110001000011
3202110102201010212102112
43013110311032301003
512001310133341121
6242153223405535
721314501005232
oct3072465166103
9673381125375
10214024121411
1182849045191
12355902b38ab
131724a925379
14a504876b19
15587976e75b
hex31d4d4ec43

214024121411 has 2 divisors, whose sum is σ = 214024121412. Its totient is φ = 214024121410.

The previous prime is 214024121359. The next prime is 214024121447. The reversal of 214024121411 is 114121420412.

214024121411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214024121411 is a prime.

It is not a weakly prime, because it can be changed into another prime (214024121471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107012060705 + 107012060706.

It is an arithmetic number, because the mean of its divisors is an integer number (107012060706).

Almost surely, 2214024121411 is an apocalyptic number.

214024121411 is a deficient number, since it is larger than the sum of its proper divisors (1).

214024121411 is an equidigital number, since it uses as much as digits as its factorization.

214024121411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 512, while the sum is 23.

Adding to 214024121411 its reverse (114121420412), we get a palindrome (328145541823).

The spelling of 214024121411 in words is "two hundred fourteen billion, twenty-four million, one hundred twenty-one thousand, four hundred eleven".