Base | Representation |
---|---|
bin | 1100011101010101001… |
… | …1101110011100101101 |
3 | 202110110021012000020221 |
4 | 3013111103232130231 |
5 | 12001314210144001 |
6 | 242154111011341 |
7 | 21314625651511 |
oct | 3072523563455 |
9 | 673407160227 |
10 | 214032115501 |
11 | 82852605276 |
12 | 35592b09b51 |
13 | 1724c493bb9 |
14 | a505958141 |
15 | 587a2ed1a1 |
hex | 31d54ee72d |
214032115501 has 2 divisors, whose sum is σ = 214032115502. Its totient is φ = 214032115500.
The previous prime is 214032115457. The next prime is 214032115547. The reversal of 214032115501 is 105511230412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 189359874025 + 24672241476 = 435155^2 + 157074^2 .
It is a cyclic number.
It is not a de Polignac number, because 214032115501 - 223 = 214023726893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214032115571) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107016057750 + 107016057751.
It is an arithmetic number, because the mean of its divisors is an integer number (107016057751).
Almost surely, 2214032115501 is an apocalyptic number.
It is an amenable number.
214032115501 is a deficient number, since it is larger than the sum of its proper divisors (1).
214032115501 is an equidigital number, since it uses as much as digits as its factorization.
214032115501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 214032115501 its reverse (105511230412), we get a palindrome (319543345913).
The spelling of 214032115501 in words is "two hundred fourteen billion, thirty-two million, one hundred fifteen thousand, five hundred one".
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