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214032144351 = 3314453351679
BaseRepresentation
bin1100011101010101001…
…1110101011111011111
3202110110021020110211110
43013111103311133133
512001314212104401
6242154111353103
721314626131564
oct3072523653737
9673407213743
10214032144351
1182852624a13
1235592b22793
131724c4a407c
14a50596486b
15587a3069d6
hex31d54f57df

214032144351 has 16 divisors (see below), whose sum is σ = 294594191360. Its totient is φ = 138079481760.

The previous prime is 214032144331. The next prime is 214032144373. The reversal of 214032144351 is 153441230412.

It is not a de Polignac number, because 214032144351 - 215 = 214032111583 is a prime.

It is a super-2 number, since 2×2140321443512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214032144311) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4115730 + ... + 4167408.

It is an arithmetic number, because the mean of its divisors is an integer number (18412136960).

Almost surely, 2214032144351 is an apocalyptic number.

214032144351 is a deficient number, since it is larger than the sum of its proper divisors (80562047009).

214032144351 is a wasteful number, since it uses less digits than its factorization.

214032144351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96246.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 214032144351 its reverse (153441230412), we get a palindrome (367473374763).

The spelling of 214032144351 in words is "two hundred fourteen billion, thirty-two million, one hundred forty-four thousand, three hundred fifty-one".

Divisors: 1 3 31 93 44533 51679 133599 155037 1380523 1602049 4141569 4806147 2301420907 6904262721 71344048117 214032144351