Base | Representation |
---|---|
bin | 110000101010100110000101… |
… | …011100001010011100010111 |
3 | 1001001211101110202012102200020 |
4 | 300222212011130022130113 |
5 | 211023210242031422403 |
6 | 2035113321050320223 |
7 | 63040253535303315 |
oct | 6052460534123427 |
9 | 1031741422172606 |
10 | 214033344014103 |
11 | 6221a038949289 |
12 | 20009119a29073 |
13 | 925734732ab93 |
14 | 3abd3aa6930b5 |
15 | 19b2772460453 |
hex | c2a98570a717 |
214033344014103 has 8 divisors (see below), whose sum is σ = 286195493430000. Its totient is φ = 142280045303808.
The previous prime is 214033344014071. The next prime is 214033344014167. The reversal of 214033344014103 is 301410443330412.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 214033344014103 - 25 = 214033344014071 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (214033344016103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 102212675178 + ... + 102212677271.
It is an arithmetic number, because the mean of its divisors is an integer number (35774436678750).
Almost surely, 2214033344014103 is an apocalyptic number.
214033344014103 is a deficient number, since it is larger than the sum of its proper divisors (72162149415897).
214033344014103 is a wasteful number, since it uses less digits than its factorization.
214033344014103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204425352801.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 214033344014103 its reverse (301410443330412), we get a palindrome (515443787344515).
The spelling of 214033344014103 in words is "two hundred fourteen trillion, thirty-three billion, three hundred forty-four million, fourteen thousand, one hundred three".
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