Base | Representation |
---|---|
bin | 110000101010100110110100… |
… | …111101010011101111111010 |
3 | 1001001211110112022022022012112 |
4 | 300222212310331103233322 |
5 | 211023213410123411442 |
6 | 2035113532125412322 |
7 | 63040312355452151 |
oct | 6052466475235772 |
9 | 1031743468268175 |
10 | 214034141232122 |
11 | 6221a407959a52 |
12 | 20009300a0a0a2 |
13 | 9257443548713 |
14 | 3abd4444d6598 |
15 | 19b27bc438082 |
hex | c2a9b4f53bfa |
214034141232122 has 4 divisors (see below), whose sum is σ = 321051211848186. Its totient is φ = 107017070616060.
The previous prime is 214034141232077. The next prime is 214034141232137. The reversal of 214034141232122 is 221232141430412.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 151625705422321 + 62408435809801 = 12313639^2 + 7899901^2 .
It is a super-2 number, since 2×2140341412321222 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53508535308029 + ... + 53508535308032.
Almost surely, 2214034141232122 is an apocalyptic number.
214034141232122 is a deficient number, since it is larger than the sum of its proper divisors (107017070616064).
214034141232122 is a wasteful number, since it uses less digits than its factorization.
214034141232122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107017070616063.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 214034141232122 its reverse (221232141430412), we get a palindrome (435266282662534).
The spelling of 214034141232122 in words is "two hundred fourteen trillion, thirty-four billion, one hundred forty-one million, two hundred thirty-two thousand, one hundred twenty-two".
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