214034141232137 has 2 divisors, whose sum is σ = 214034141232138. Its totient is φ = 214034141232136.

The previous prime is 214034141232077. The next prime is 214034141232139. The reversal of 214034141232137 is 731232141430412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 200618301112441 + 13415840119696 = 14163979^2 + 3662764^2 .

It is a cyclic number.

It is not a de Polignac number, because 214034141232137 - 2³⁰ = 214033067490313 is a prime.

It is a super-2 number, since 2×214034141232137² (a number of 29 digits) contains 22 as substring.

Together with 214034141232139, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 214034141232137.

It is not a weakly prime, because it can be changed into another prime (214034141232139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107017070616068 + 107017070616069.

It is an arithmetic number, because the mean of its divisors is an integer number (107017070616069).

Almost surely, 2^{214034141232137} is an apocalyptic number.

It is an amenable number.

214034141232137 is a deficient number, since it is larger than the sum of its proper divisors (1).

214034141232137 is an equidigital number, since it uses as much as digits as its factorization.

214034141232137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 38.

Adding to 214034141232137 its reverse (731232141430412), we get a palindrome (945266282662549).

The spelling of 214034141232137 in words is "two hundred fourteen trillion, thirty-four billion, one hundred forty-one million, two hundred thirty-two thousand, one hundred thirty-seven".