Base | Representation |
---|---|
bin | 10011111011110010… |
… | …001101100111111011 |
3 | 2001020200121121201212 |
4 | 103323302031213323 |
5 | 322313423112103 |
6 | 13455524233335 |
7 | 1355261650661 |
oct | 237362154773 |
9 | 61220547655 |
10 | 21404113403 |
11 | 9094078222 |
12 | 419423b84b |
13 | 203156677a |
14 | 1070988c31 |
15 | 8541747d8 |
hex | 4fbc8d9fb |
21404113403 has 2 divisors, whose sum is σ = 21404113404. Its totient is φ = 21404113402.
The previous prime is 21404113391. The next prime is 21404113439. The reversal of 21404113403 is 30431140412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21404113403 - 220 = 21403064827 is a prime.
It is not a weakly prime, because it can be changed into another prime (21404113303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10702056701 + 10702056702.
It is an arithmetic number, because the mean of its divisors is an integer number (10702056702).
Almost surely, 221404113403 is an apocalyptic number.
21404113403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21404113403 is an equidigital number, since it uses as much as digits as its factorization.
21404113403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 21404113403 its reverse (30431140412), we get a palindrome (51835253815).
The spelling of 21404113403 in words is "twenty-one billion, four hundred four million, one hundred thirteen thousand, four hundred three".
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