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21404114117 is a prime number
BaseRepresentation
bin10011111011110010…
…001101110011000101
32001020200121122201022
4103323302031303011
5322313423122432
613455524240525
71355261653031
oct237362156305
961220548638
1021404114117
119094078811
124194240145
132031566ba9
1410709891c1
15854174b12
hex4fbc8dcc5

21404114117 has 2 divisors, whose sum is σ = 21404114118. Its totient is φ = 21404114116.

The previous prime is 21404114059. The next prime is 21404114159. The reversal of 21404114117 is 71141140412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20644229761 + 759884356 = 143681^2 + 27566^2 .

It is a cyclic number.

It is not a de Polignac number, because 21404114117 - 222 = 21399919813 is a prime.

It is a super-2 number, since 2×214041141172 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21404111117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10702057058 + 10702057059.

It is an arithmetic number, because the mean of its divisors is an integer number (10702057059).

Almost surely, 221404114117 is an apocalyptic number.

It is an amenable number.

21404114117 is a deficient number, since it is larger than the sum of its proper divisors (1).

21404114117 is an equidigital number, since it uses as much as digits as its factorization.

21404114117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 896, while the sum is 26.

Adding to 21404114117 its reverse (71141140412), we get a palindrome (92545254529).

The spelling of 21404114117 in words is "twenty-one billion, four hundred four million, one hundred fourteen thousand, one hundred seventeen".