Base | Representation |
---|---|
bin | 111111110010110… |
… | …0011111110011101 |
3 | 12112011211100212002 |
4 | 1333211203332131 |
5 | 13340440144432 |
6 | 552223252045 |
7 | 104021254433 |
oct | 17745437635 |
9 | 5464740762 |
10 | 2140553117 |
11 | 9a931726a |
12 | 4b8a4a025 |
13 | 2816193a1 |
14 | 164404d53 |
15 | c7dc7e62 |
hex | 7f963f9d |
2140553117 has 2 divisors, whose sum is σ = 2140553118. Its totient is φ = 2140553116.
The previous prime is 2140553081. The next prime is 2140553137. The reversal of 2140553117 is 7113550412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1953109636 + 187443481 = 44194^2 + 13691^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2140553117 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2140553117.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2140553137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070276558 + 1070276559.
It is an arithmetic number, because the mean of its divisors is an integer number (1070276559).
Almost surely, 22140553117 is an apocalyptic number.
It is an amenable number.
2140553117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140553117 is an equidigital number, since it uses as much as digits as its factorization.
2140553117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 29.
The square root of 2140553117 is about 46266.1119719390. Note that the first 3 decimals coincide. The cubic root of 2140553117 is about 1288.7697577534.
The spelling of 2140553117 in words is "two billion, one hundred forty million, five hundred fifty-three thousand, one hundred seventeen".
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