Base | Representation |
---|---|
bin | 1100011101011101010… |
… | …1110001000111001011 |
3 | 202110112122022221102211 |
4 | 3013113111301013023 |
5 | 12001401422031011 |
6 | 242201325405551 |
7 | 21315521502262 |
oct | 3072725610713 |
9 | 673478287384 |
10 | 214066205131 |
11 | 8286a879319 |
12 | 355a24098b7 |
13 | 1725656b48c |
14 | a50a2ad5d9 |
15 | 587d2d3b21 |
hex | 31d75711cb |
214066205131 has 2 divisors, whose sum is σ = 214066205132. Its totient is φ = 214066205130.
The previous prime is 214066205117. The next prime is 214066205161. The reversal of 214066205131 is 131502660412.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 214066205131 - 29 = 214066204619 is a prime.
It is a super-2 number, since 2×2140662051312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 214066205093 and 214066205102.
It is not a weakly prime, because it can be changed into another prime (214066205161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107033102565 + 107033102566.
It is an arithmetic number, because the mean of its divisors is an integer number (107033102566).
Almost surely, 2214066205131 is an apocalyptic number.
214066205131 is a deficient number, since it is larger than the sum of its proper divisors (1).
214066205131 is an equidigital number, since it uses as much as digits as its factorization.
214066205131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 214066205131 its reverse (131502660412), we get a palindrome (345568865543).
The spelling of 214066205131 in words is "two hundred fourteen billion, sixty-six million, two hundred five thousand, one hundred thirty-one".
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