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214113434300137 is a prime number
BaseRepresentation
bin110000101011110000101011…
…001100010110111011101001
31001002010001012101012111211101
4300223300223030112323221
5211031013303140101022
62035214204231201401
763046120334431441
oct6053605314267351
91032101171174741
10214113434300137
116224aaa7811619
122002074bb16261
139261a6c084b88
143ac3207411121
1519b48ad815627
hexc2bc2b316ee9

214113434300137 has 2 divisors, whose sum is σ = 214113434300138. Its totient is φ = 214113434300136.

The previous prime is 214113434300039. The next prime is 214113434300189. The reversal of 214113434300137 is 731003434311412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212629591166976 + 1483843133161 = 14581824^2 + 1218131^2 .

It is a cyclic number.

It is not a de Polignac number, because 214113434300137 - 27 = 214113434300009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214113434300096 and 214113434300105.

It is not a weakly prime, because it can be changed into another prime (214113434303137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107056717150068 + 107056717150069.

It is an arithmetic number, because the mean of its divisors is an integer number (107056717150069).

Almost surely, 2214113434300137 is an apocalyptic number.

It is an amenable number.

214113434300137 is a deficient number, since it is larger than the sum of its proper divisors (1).

214113434300137 is an equidigital number, since it uses as much as digits as its factorization.

214113434300137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72576, while the sum is 37.

Adding to 214113434300137 its reverse (731003434311412), we get a palindrome (945116868611549).

The spelling of 214113434300137 in words is "two hundred fourteen trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred thousand, one hundred thirty-seven".