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214113434300039 is a prime number
BaseRepresentation
bin110000101011110000101011…
…001100010110111010000111
31001002010001012101012111200202
4300223300223030112322013
5211031013303140100124
62035214204231201115
763046120334431241
oct6053605314267207
91032101171174622
10214113434300039
116224aaa781153a
122002074bb1619b
139261a6c084b11
143ac3207411091
1519b48ad8155ae
hexc2bc2b316e87

214113434300039 has 2 divisors, whose sum is σ = 214113434300040. Its totient is φ = 214113434300038.

The previous prime is 214113434300009. The next prime is 214113434300137. The reversal of 214113434300039 is 930003434311412.

214113434300039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214113434300039 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214113434299975 and 214113434300011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214113434300009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107056717150019 + 107056717150020.

It is an arithmetic number, because the mean of its divisors is an integer number (107056717150020).

Almost surely, 2214113434300039 is an apocalyptic number.

214113434300039 is a deficient number, since it is larger than the sum of its proper divisors (1).

214113434300039 is an equidigital number, since it uses as much as digits as its factorization.

214113434300039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 38.

The spelling of 214113434300039 in words is "two hundred fourteen trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred thousand, thirty-nine".