Base | Representation |
---|---|
bin | 110000101011110000101011… |
… | …001100010111000001111111 |
3 | 1001002010001012101012112101102 |
4 | 300223300223030113001333 |
5 | 211031013303140104133 |
6 | 2035214204231203315 |
7 | 63046120334432561 |
oct | 6053605314270177 |
9 | 1032101171175342 |
10 | 214113434300543 |
11 | 6224aaa7811958 |
12 | 2002074bb1653b |
13 | 9261a6c08510b |
14 | 3ac3207411331 |
15 | 19b48ad8157e8 |
hex | c2bc2b31707f |
214113434300543 has 2 divisors, whose sum is σ = 214113434300544. Its totient is φ = 214113434300542.
The previous prime is 214113434300509. The next prime is 214113434300573. The reversal of 214113434300543 is 345003434311412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214113434300543 - 216 = 214113434235007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214113434300497 and 214113434300506.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214113434300573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107056717150271 + 107056717150272.
It is an arithmetic number, because the mean of its divisors is an integer number (107056717150272).
Almost surely, 2214113434300543 is an apocalyptic number.
214113434300543 is a deficient number, since it is larger than the sum of its proper divisors (1).
214113434300543 is an equidigital number, since it uses as much as digits as its factorization.
214113434300543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 214113434300543 its reverse (345003434311412), we get a palindrome (559116868611955).
The spelling of 214113434300543 in words is "two hundred fourteen trillion, one hundred thirteen billion, four hundred thirty-four million, three hundred thousand, five hundred forty-three".
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