Base | Representation |
---|---|
bin | 111111110100000… |
… | …0100111100010001 |
3 | 12112020001212021012 |
4 | 1333220010330101 |
5 | 13341122244213 |
6 | 552245340305 |
7 | 104030001563 |
oct | 17750047421 |
9 | 5466055235 |
10 | 2141212433 |
11 | 9a9727658 |
12 | 4b9107695 |
13 | 2817ba509 |
14 | 164537333 |
15 | c7ea84a8 |
hex | 7fa04f11 |
2141212433 has 2 divisors, whose sum is σ = 2141212434. Its totient is φ = 2141212432.
The previous prime is 2141212399. The next prime is 2141212457. The reversal of 2141212433 is 3342121412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2141190529 + 21904 = 46273^2 + 148^2 .
It is a cyclic number.
It is not a de Polignac number, because 2141212433 - 210 = 2141211409 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2141212399 and 2141212408.
It is not a weakly prime, because it can be changed into another prime (2141214433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070606216 + 1070606217.
It is an arithmetic number, because the mean of its divisors is an integer number (1070606217).
Almost surely, 22141212433 is an apocalyptic number.
It is an amenable number.
2141212433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141212433 is an equidigital number, since it uses as much as digits as its factorization.
2141212433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1152, while the sum is 23.
The square root of 2141212433 is about 46273.2366816932. The cubic root of 2141212433 is about 1288.9020630113.
Adding to 2141212433 its reverse (3342121412), we get a palindrome (5483333845).
The spelling of 2141212433 in words is "two billion, one hundred forty-one million, two hundred twelve thousand, four hundred thirty-three".
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