Base | Representation |
---|---|
bin | 1100011101101011001… |
… | …0011010000000010011 |
3 | 202110200200011110212112 |
4 | 3013122302122000103 |
5 | 12002011223404212 |
6 | 242211153215535 |
7 | 21320123226515 |
oct | 3073262320023 |
9 | 673620143775 |
10 | 214124044307 |
11 | 8289a493798 |
12 | 355b98615ab |
13 | 1726553ca44 |
14 | a513c47bb5 |
15 | 588340b422 |
hex | 31dac9a013 |
214124044307 has 2 divisors, whose sum is σ = 214124044308. Its totient is φ = 214124044306.
The previous prime is 214124044237. The next prime is 214124044313. The reversal of 214124044307 is 703440421412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214124044307 - 210 = 214124043283 is a prime.
It is a super-2 number, since 2×2141240443072 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (214124044397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107062022153 + 107062022154.
It is an arithmetic number, because the mean of its divisors is an integer number (107062022154).
Almost surely, 2214124044307 is an apocalyptic number.
214124044307 is a deficient number, since it is larger than the sum of its proper divisors (1).
214124044307 is an equidigital number, since it uses as much as digits as its factorization.
214124044307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 214124044307 its reverse (703440421412), we get a palindrome (917564465719).
The spelling of 214124044307 in words is "two hundred fourteen billion, one hundred twenty-four million, forty-four thousand, three hundred seven".
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