Base | Representation |
---|---|
bin | 110000101100000010000110… |
… | …010110011010100110110111 |
3 | 1001002011211111020220222201021 |
4 | 300230002012112122212313 |
5 | 211031320112221014341 |
6 | 2035230540531042011 |
7 | 63050352064326343 |
oct | 6054020626324667 |
9 | 1032154436828637 |
10 | 214132143532471 |
11 | 62257a286797aa |
12 | 200242b1740307 |
13 | 9263761207b58 |
14 | 3ac40a00da623 |
15 | 19b51060b69d1 |
hex | c2c08659a9b7 |
214132143532471 has 2 divisors, whose sum is σ = 214132143532472. Its totient is φ = 214132143532470.
The previous prime is 214132143532399. The next prime is 214132143532477. The reversal of 214132143532471 is 174235341231412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214132143532471 - 217 = 214132143401399 is a prime.
It is a super-3 number, since 3×2141321435324713 (a number of 44 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214132143532477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107066071766235 + 107066071766236.
It is an arithmetic number, because the mean of its divisors is an integer number (107066071766236).
Almost surely, 2214132143532471 is an apocalyptic number.
214132143532471 is a deficient number, since it is larger than the sum of its proper divisors (1).
214132143532471 is an equidigital number, since it uses as much as digits as its factorization.
214132143532471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 483840, while the sum is 43.
Adding to 214132143532471 its reverse (174235341231412), we get a palindrome (388367484763883).
The spelling of 214132143532471 in words is "two hundred fourteen trillion, one hundred thirty-two billion, one hundred forty-three million, five hundred thirty-two thousand, four hundred seventy-one".
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