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214132143532471 is a prime number
BaseRepresentation
bin110000101100000010000110…
…010110011010100110110111
31001002011211111020220222201021
4300230002012112122212313
5211031320112221014341
62035230540531042011
763050352064326343
oct6054020626324667
91032154436828637
10214132143532471
1162257a286797aa
12200242b1740307
139263761207b58
143ac40a00da623
1519b51060b69d1
hexc2c08659a9b7

214132143532471 has 2 divisors, whose sum is σ = 214132143532472. Its totient is φ = 214132143532470.

The previous prime is 214132143532399. The next prime is 214132143532477. The reversal of 214132143532471 is 174235341231412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 214132143532471 - 217 = 214132143401399 is a prime.

It is a super-3 number, since 3×2141321435324713 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (214132143532477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107066071766235 + 107066071766236.

It is an arithmetic number, because the mean of its divisors is an integer number (107066071766236).

Almost surely, 2214132143532471 is an apocalyptic number.

214132143532471 is a deficient number, since it is larger than the sum of its proper divisors (1).

214132143532471 is an equidigital number, since it uses as much as digits as its factorization.

214132143532471 is an evil number, because the sum of its binary digits is even.

The product of its digits is 483840, while the sum is 43.

Adding to 214132143532471 its reverse (174235341231412), we get a palindrome (388367484763883).

The spelling of 214132143532471 in words is "two hundred fourteen trillion, one hundred thirty-two billion, one hundred forty-three million, five hundred thirty-two thousand, four hundred seventy-one".