2141343314111 has 4 divisors (see below), whose sum is σ = 2142722158752. Its totient is φ = 2139964469472.

The previous prime is 2141343314107. The next prime is 2141343314113. The reversal of 2141343314111 is 1114133431412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2141343314111 - 2² = 2141343314107 is a prime.

It is a super-3 number, since 3×2141343314111³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2141343314113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 689419991 + ... + 689423096.

It is an arithmetic number, because the mean of its divisors is an integer number (535680539688).

Almost surely, 2^{2141343314111} is an apocalyptic number.

2141343314111 is a deficient number, since it is larger than the sum of its proper divisors (1378844641).

2141343314111 is a wasteful number, since it uses less digits than its factorization.

2141343314111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1378844640.

The product of its digits is 3456, while the sum is 29.

Adding to 2141343314111 its reverse (1114133431412), we get a palindrome (3255476745523).

The spelling of 2141343314111 in words is "two trillion, one hundred forty-one billion, three hundred forty-three million, three hundred fourteen thousand, one hundred eleven".