Base | Representation |
---|---|
bin | 111111110100010… |
… | …0101011011111101 |
3 | 12112020022121211211 |
4 | 1333220211123331 |
5 | 13341141024113 |
6 | 552252244421 |
7 | 104031064615 |
oct | 17750453375 |
9 | 5466277754 |
10 | 2141345533 |
11 | 9a9808658 |
12 | 4b9170711 |
13 | 281835c82 |
14 | 16456da45 |
15 | c7ed2b3d |
hex | 7fa256fd |
2141345533 has 2 divisors, whose sum is σ = 2141345534. Its totient is φ = 2141345532.
The previous prime is 2141345501. The next prime is 2141345537. The reversal of 2141345533 is 3355431412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2140172644 + 1172889 = 46262^2 + 1083^2 .
It is a cyclic number.
It is not a de Polignac number, because 2141345533 - 25 = 2141345501 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2141345495 and 2141345504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2141345537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070672766 + 1070672767.
It is an arithmetic number, because the mean of its divisors is an integer number (1070672767).
Almost surely, 22141345533 is an apocalyptic number.
It is an amenable number.
2141345533 is a deficient number, since it is larger than the sum of its proper divisors (1).
2141345533 is an equidigital number, since it uses as much as digits as its factorization.
2141345533 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 31.
The square root of 2141345533 is about 46274.6748556919. The cubic root of 2141345533 is about 1288.9287689572.
Adding to 2141345533 its reverse (3355431412), we get a palindrome (5496776945).
The spelling of 2141345533 in words is "two billion, one hundred forty-one million, three hundred forty-five thousand, five hundred thirty-three".
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