Search a number
-
+
214146011023481 is a prime number
BaseRepresentation
bin110000101100001111000000…
…111010101100100001111001
31001002020011021201001112010102
4300230033000322230201321
5211032032012310222411
62035241152551325145
763051352533134315
oct6054170072544171
91032204251045112
10214146011023481
11622628a44a1a79
1220026b219807b5
139264b61230234
143ac4a17b5cb45
1519b5668772d3b
hexc2c3c0eac879

214146011023481 has 2 divisors, whose sum is σ = 214146011023482. Its totient is φ = 214146011023480.

The previous prime is 214146011023423. The next prime is 214146011023487. The reversal of 214146011023481 is 184320110641412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212416312591081 + 1729698432400 = 14574509^2 + 1315180^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214146011023481 is a prime.

It is a super-2 number, since 2×2141460110234812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (214146011023487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107073005511740 + 107073005511741.

It is an arithmetic number, because the mean of its divisors is an integer number (107073005511741).

Almost surely, 2214146011023481 is an apocalyptic number.

It is an amenable number.

214146011023481 is a deficient number, since it is larger than the sum of its proper divisors (1).

214146011023481 is an equidigital number, since it uses as much as digits as its factorization.

214146011023481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36864, while the sum is 38.

Adding to 214146011023481 its reverse (184320110641412), we get a palindrome (398466121664893).

The spelling of 214146011023481 in words is "two hundred fourteen trillion, one hundred forty-six billion, eleven million, twenty-three thousand, four hundred eighty-one".