Base | Representation |
---|---|
bin | 110000101100001111000000… |
… | …111010101100100000111111 |
3 | 1001002020011021201001112001021 |
4 | 300230033000322230200333 |
5 | 211032032012310222143 |
6 | 2035241152551325011 |
7 | 63051352533134203 |
oct | 6054170072544077 |
9 | 1032204251045037 |
10 | 214146011023423 |
11 | 622628a44a1a26 |
12 | 20026b21980767 |
13 | 9264b612301bb |
14 | 3ac4a17b5cb03 |
15 | 19b5668772ced |
hex | c2c3c0eac83f |
214146011023423 has 2 divisors, whose sum is σ = 214146011023424. Its totient is φ = 214146011023422.
The previous prime is 214146011023319. The next prime is 214146011023481. The reversal of 214146011023423 is 324320110641412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214146011023423 - 217 = 214146010892351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214146011023523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107073005511711 + 107073005511712.
It is an arithmetic number, because the mean of its divisors is an integer number (107073005511712).
Almost surely, 2214146011023423 is an apocalyptic number.
214146011023423 is a deficient number, since it is larger than the sum of its proper divisors (1).
214146011023423 is an equidigital number, since it uses as much as digits as its factorization.
214146011023423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 214146011023423 its reverse (324320110641412), we get a palindrome (538466121664835).
The spelling of 214146011023423 in words is "two hundred fourteen trillion, one hundred forty-six billion, eleven million, twenty-three thousand, four hundred twenty-three".
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