Base | Representation |
---|---|
bin | 1001101111010001001011… |
… | …10011111100010101001111 |
3 | 2210211021201221211122220211 |
4 | 10313220211303330111033 |
5 | 10301332104333430221 |
6 | 113314023314223251 |
7 | 4340131056460033 |
oct | 467504563742517 |
9 | 83737657748824 |
10 | 21415341311311 |
11 | 6907216967602 |
12 | 249a52a584b27 |
13 | bc45c536a0bc |
14 | 5407181361c3 |
15 | 2720dec796e1 |
hex | 137a25cfc54f |
21415341311311 has 2 divisors, whose sum is σ = 21415341311312. Its totient is φ = 21415341311310.
The previous prime is 21415341311303. The next prime is 21415341311321. The reversal of 21415341311311 is 11311314351412.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21415341311311 - 23 = 21415341311303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21415341311321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10707670655655 + 10707670655656.
It is an arithmetic number, because the mean of its divisors is an integer number (10707670655656).
Almost surely, 221415341311311 is an apocalyptic number.
21415341311311 is a deficient number, since it is larger than the sum of its proper divisors (1).
21415341311311 is an equidigital number, since it uses as much as digits as its factorization.
21415341311311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4320, while the sum is 31.
Adding to 21415341311311 its reverse (11311314351412), we get a palindrome (32726655662723).
The spelling of 21415341311311 in words is "twenty-one trillion, four hundred fifteen billion, three hundred forty-one million, three hundred eleven thousand, three hundred eleven".
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