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21421121131 is a prime number
BaseRepresentation
bin10011111100110011…
…000101111001101011
32001021212121200221201
4103330303011321223
5322332301334011
613501332545031
71355556345124
oct237463057153
961255550851
1021421121131
1190a27343a3
124199a82177
132034c3cc07
141072d3504b
158558d3cc1
hex4fccc5e6b

21421121131 has 2 divisors, whose sum is σ = 21421121132. Its totient is φ = 21421121130.

The previous prime is 21421121119. The next prime is 21421121143. The reversal of 21421121131 is 13112112412.

It is a balanced prime because it is at equal distance from previous prime (21421121119) and next prime (21421121143).

It is a cyclic number.

It is not a de Polignac number, because 21421121131 - 219 = 21420596843 is a prime.

It is a super-2 number, since 2×214211211312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21421121099 and 21421121108.

It is not a weakly prime, because it can be changed into another prime (21421121171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10710560565 + 10710560566.

It is an arithmetic number, because the mean of its divisors is an integer number (10710560566).

Almost surely, 221421121131 is an apocalyptic number.

21421121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

21421121131 is an equidigital number, since it uses as much as digits as its factorization.

21421121131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 96, while the sum is 19.

Adding to 21421121131 its reverse (13112112412), we get a palindrome (34533233543).

The spelling of 21421121131 in words is "twenty-one billion, four hundred twenty-one million, one hundred twenty-one thousand, one hundred thirty-one".