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214231112120107 is a prime number
BaseRepresentation
bin110000101101011110010001…
…010101100111011100101011
31001002112021221112210011012001
4300231132101111213130223
5211034430304200320412
62035344225251231431
763060454445413615
oct6055362125473453
91032467845704161
10214231112120107
11622959a4886495
122003b511ba8577
13926cba412c604
143ac8bac193db5
1519b79999b7957
hexc2d79156772b

214231112120107 has 2 divisors, whose sum is σ = 214231112120108. Its totient is φ = 214231112120106.

The previous prime is 214231112120071. The next prime is 214231112120147. The reversal of 214231112120107 is 701021211132412.

Together with previous prime (214231112120071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 214231112120107 - 219 = 214231111595819 is a prime.

It is a super-3 number, since 3×2142311121201073 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (214231112120147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107115556060053 + 107115556060054.

It is an arithmetic number, because the mean of its divisors is an integer number (107115556060054).

Almost surely, 2214231112120107 is an apocalyptic number.

214231112120107 is a deficient number, since it is larger than the sum of its proper divisors (1).

214231112120107 is an equidigital number, since it uses as much as digits as its factorization.

214231112120107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 214231112120107 its reverse (701021211132412), we get a palindrome (915252323252519).

The spelling of 214231112120107 in words is "two hundred fourteen trillion, two hundred thirty-one billion, one hundred twelve million, one hundred twenty thousand, one hundred seven".