Base | Representation |
---|---|
bin | 110000101101011110010001… |
… | …010101100111011101010011 |
3 | 1001002112021221112210011020112 |
4 | 300231132101111213131103 |
5 | 211034430304200321042 |
6 | 2035344225251231535 |
7 | 63060454445414003 |
oct | 6055362125473523 |
9 | 1032467845704215 |
10 | 214231112120147 |
11 | 622959a4886521 |
12 | 2003b511ba85ab |
13 | 926cba412c635 |
14 | 3ac8bac194003 |
15 | 19b79999b7982 |
hex | c2d791567753 |
214231112120147 has 2 divisors, whose sum is σ = 214231112120148. Its totient is φ = 214231112120146.
The previous prime is 214231112120107. The next prime is 214231112120161. The reversal of 214231112120147 is 741021211132412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214231112120147 - 212 = 214231112116051 is a prime.
It is not a weakly prime, because it can be changed into another prime (214231112120107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107115556060073 + 107115556060074.
It is an arithmetic number, because the mean of its divisors is an integer number (107115556060074).
Almost surely, 2214231112120147 is an apocalyptic number.
214231112120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
214231112120147 is an equidigital number, since it uses as much as digits as its factorization.
214231112120147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 32.
Adding to 214231112120147 its reverse (741021211132412), we get a palindrome (955252323252559).
The spelling of 214231112120147 in words is "two hundred fourteen trillion, two hundred thirty-one billion, one hundred twelve million, one hundred twenty thousand, one hundred forty-seven".
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