Base | Representation |
---|---|
bin | 1100011110000101011… |
… | …0000001011111010011 |
3 | 202110222100011001120222 |
4 | 3013201112001133103 |
5 | 12002222403404441 |
6 | 242230123023255 |
7 | 21322630221434 |
oct | 3074126013723 |
9 | 673870131528 |
10 | 214234044371 |
11 | 82946595436 |
12 | 3562a66ab2b |
13 | 17282275139 |
14 | a5246bd48b |
15 | 588cdd8d4b |
hex | 31e15817d3 |
214234044371 has 2 divisors, whose sum is σ = 214234044372. Its totient is φ = 214234044370.
The previous prime is 214234044347. The next prime is 214234044373. The reversal of 214234044371 is 173440432412.
214234044371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214234044371 - 222 = 214229850067 is a prime.
Together with 214234044373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (214234044373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107117022185 + 107117022186.
It is an arithmetic number, because the mean of its divisors is an integer number (107117022186).
Almost surely, 2214234044371 is an apocalyptic number.
214234044371 is a deficient number, since it is larger than the sum of its proper divisors (1).
214234044371 is an equidigital number, since it uses as much as digits as its factorization.
214234044371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 35.
Adding to 214234044371 its reverse (173440432412), we get a palindrome (387674476783).
The spelling of 214234044371 in words is "two hundred fourteen billion, two hundred thirty-four million, forty-four thousand, three hundred seventy-one".
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