Base | Representation |
---|---|
bin | 1100011110010101001… |
… | …0110110000011111111 |
3 | 202111010221212012122212 |
4 | 3013211102312003333 |
5 | 12002341340214444 |
6 | 242240451331035 |
7 | 21324363444023 |
oct | 3074522660377 |
9 | 674127765585 |
10 | 214300319999 |
11 | 8297aa42287 |
12 | 356488b0a7b |
13 | 17292c0b69c |
14 | a52d412383 |
15 | 5893b2b19e |
hex | 31e54b60ff |
214300319999 has 2 divisors, whose sum is σ = 214300320000. Its totient is φ = 214300319998.
The previous prime is 214300319923. The next prime is 214300320011. The reversal of 214300319999 is 999913003412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214300319999 - 212 = 214300315903 is a prime.
It is a super-3 number, since 3×2143003199993 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214300319099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107150159999 + 107150160000.
It is an arithmetic number, because the mean of its divisors is an integer number (107150160000).
Almost surely, 2214300319999 is an apocalyptic number.
214300319999 is a deficient number, since it is larger than the sum of its proper divisors (1).
214300319999 is an equidigital number, since it uses as much as digits as its factorization.
214300319999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 472392, while the sum is 50.
The spelling of 214300319999 in words is "two hundred fourteen billion, three hundred million, three hundred nineteen thousand, nine hundred ninety-nine".
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