Base | Representation |
---|---|
bin | 1100011110011000010… |
… | …1110000011100101111 |
3 | 202111011212222021102012 |
4 | 3013212011300130233 |
5 | 12002403244310401 |
6 | 242242045351435 |
7 | 21324615051461 |
oct | 3074605603457 |
9 | 674155867365 |
10 | 214313666351 |
11 | 82987528624 |
12 | 3565126857b |
13 | 17295902435 |
14 | a5310c8131 |
15 | 5894db58bb |
hex | 31e617072f |
214313666351 has 2 divisors, whose sum is σ = 214313666352. Its totient is φ = 214313666350.
The previous prime is 214313666311. The next prime is 214313666363. The reversal of 214313666351 is 153666313412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214313666351 - 226 = 214246557487 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 214313666299 and 214313666308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214313666311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107156833175 + 107156833176.
It is an arithmetic number, because the mean of its divisors is an integer number (107156833176).
Almost surely, 2214313666351 is an apocalyptic number.
214313666351 is a deficient number, since it is larger than the sum of its proper divisors (1).
214313666351 is an equidigital number, since it uses as much as digits as its factorization.
214313666351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 233280, while the sum is 41.
Adding to 214313666351 its reverse (153666313412), we get a palindrome (367979979763).
The spelling of 214313666351 in words is "two hundred fourteen billion, three hundred thirteen million, six hundred sixty-six thousand, three hundred fifty-one".
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