214314120131 has 2 divisors, whose sum is σ = 214314120132. Its totient is φ = 214314120130.

The previous prime is 214314120107. The next prime is 214314120149. The reversal of 214314120131 is 131021413412.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-214314120131 is a prime.

It is a super-2 number, since 2×214314120131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 214314120097 and 214314120106.

It is not a weakly prime, because it can be changed into another prime (214314120161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107157060065 + 107157060066.

It is an arithmetic number, because the mean of its divisors is an integer number (107157060066).

Almost surely, 2^214314120131 is an apocalyptic number.

214314120131 is a deficient number, since it is larger than the sum of its proper divisors (1).

214314120131 is an equidigital number, since it uses as much as digits as its factorization.

214314120131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 214314120131 its reverse (131021413412), we get a palindrome (345335533543).

The spelling of 214314120131 in words is "two hundred fourteen billion, three hundred fourteen million, one hundred twenty thousand, one hundred thirty-one".