Base | Representation |
---|---|
bin | 11111001100000110101… |
… | …010010110000010001111 |
3 | 21120220020021220200011011 |
4 | 133030012222112002033 |
5 | 240103434403204203 |
6 | 4320341342510051 |
7 | 310563661116664 |
oct | 37140652260217 |
9 | 7526207820134 |
10 | 2143300444303 |
11 | 756a72252647 |
12 | 2a7476b95327 |
13 | 12715cb32995 |
14 | 75a44571a6b |
15 | 3ab4383d76d |
hex | 1f306a9608f |
2143300444303 has 2 divisors, whose sum is σ = 2143300444304. Its totient is φ = 2143300444302.
The previous prime is 2143300444283. The next prime is 2143300444319. The reversal of 2143300444303 is 3034440033412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2143300444303 - 213 = 2143300436111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2143300447303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071650222151 + 1071650222152.
It is an arithmetic number, because the mean of its divisors is an integer number (1071650222152).
Almost surely, 22143300444303 is an apocalyptic number.
2143300444303 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143300444303 is an equidigital number, since it uses as much as digits as its factorization.
2143300444303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 2143300444303 its reverse (3034440033412), we get a palindrome (5177740477715).
The spelling of 2143300444303 in words is "two trillion, one hundred forty-three billion, three hundred million, four hundred forty-four thousand, three hundred three".
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