Base | Representation |
---|---|
bin | 1100011110011100101… |
… | …1110100101111011101 |
3 | 202111020011112110002222 |
4 | 3013213023310233131 |
5 | 12002423000042023 |
6 | 242243543155125 |
7 | 21325230141506 |
oct | 3074713645735 |
9 | 674204473088 |
10 | 214332034013 |
11 | 82996933509 |
12 | 35657445aa5 |
13 | 17299663886 |
14 | a533709bad |
15 | 58967e2cc8 |
hex | 31e72f4bdd |
214332034013 has 2 divisors, whose sum is σ = 214332034014. Its totient is φ = 214332034012.
The previous prime is 214332034009. The next prime is 214332034031. The reversal of 214332034013 is 310430233412.
Together with next prime (214332034031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 205787435044 + 8544598969 = 453638^2 + 92437^2 .
It is a cyclic number.
It is not a de Polignac number, because 214332034013 - 22 = 214332034009 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (214332030013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107166017006 + 107166017007.
It is an arithmetic number, because the mean of its divisors is an integer number (107166017007).
Almost surely, 2214332034013 is an apocalyptic number.
It is an amenable number.
214332034013 is a deficient number, since it is larger than the sum of its proper divisors (1).
214332034013 is an equidigital number, since it uses as much as digits as its factorization.
214332034013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 214332034013 its reverse (310430233412), we get a palindrome (524762267425).
The spelling of 214332034013 in words is "two hundred fourteen billion, three hundred thirty-two million, thirty-four thousand, thirteen".
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