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214335013 = 713018803
BaseRepresentation
bin11001100011001…
…11111000100101
3112221022100100211
430301213320211
5414332210023
633133535421
75211550264
oct1461477045
9487270324
10214335013
11aaa94082
125b944571
1335536069
14206745db
1513c3ba0d
hexcc67e25

214335013 has 4 divisors (see below), whose sum is σ = 217353888. Its totient is φ = 211316140.

The previous prime is 214335001. The next prime is 214335019. The reversal of 214335013 is 310533412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-214335013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214335019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1509331 + ... + 1509472.

It is an arithmetic number, because the mean of its divisors is an integer number (54338472).

Almost surely, 2214335013 is an apocalyptic number.

It is an amenable number.

214335013 is a deficient number, since it is larger than the sum of its proper divisors (3018875).

214335013 is an equidigital number, since it uses as much as digits as its factorization.

214335013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3018874.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 214335013 is about 14640.1848690513. The cubic root of 214335013 is about 598.4543671545.

Adding to 214335013 its reverse (310533412), we get a palindrome (524868425).

The spelling of 214335013 in words is "two hundred fourteen million, three hundred thirty-five thousand, thirteen".

Divisors: 1 71 3018803 214335013