Base | Representation |
---|---|
bin | 1001101111110100001011… |
… | …10101100111010010001111 |
3 | 2210220002020112021022012211 |
4 | 10313322011311213102033 |
5 | 10302134100322400221 |
6 | 113330412053011251 |
7 | 4341364530610252 |
oct | 467720565472217 |
9 | 83802215238184 |
10 | 21434132231311 |
11 | 6914189948958 |
12 | 24a20b3623b27 |
13 | bc62cb3c1687 |
14 | 5415bba07099 |
15 | 27283e7b46e1 |
hex | 137e85d6748f |
21434132231311 has 4 divisors (see below), whose sum is σ = 21456206518824. Its totient is φ = 21412057943800.
The previous prime is 21434132231299. The next prime is 21434132231371. The reversal of 21434132231311 is 11313223143412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21434132231311 - 229 = 21433595360399 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21434132231371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11037142300 + ... + 11037144241.
It is an arithmetic number, because the mean of its divisors is an integer number (5364051629706).
Almost surely, 221434132231311 is an apocalyptic number.
21434132231311 is a deficient number, since it is larger than the sum of its proper divisors (22074287513).
21434132231311 is an equidigital number, since it uses as much as digits as its factorization.
21434132231311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22074287512.
The product of its digits is 10368, while the sum is 31.
Adding to 21434132231311 its reverse (11313223143412), we get a palindrome (32747355374723).
The spelling of 21434132231311 in words is "twenty-one trillion, four hundred thirty-four billion, one hundred thirty-two million, two hundred thirty-one thousand, three hundred eleven".
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