Base | Representation |
---|---|
bin | 1100011110011111010… |
… | …1101010110001001011 |
3 | 202111020221011202000120 |
4 | 3013213311222301023 |
5 | 12002433302100321 |
6 | 242245014234323 |
7 | 21325422315621 |
oct | 3074765526113 |
9 | 674227152016 |
10 | 214343003211 |
11 | 829a2045867 |
12 | 3565b0559a3 |
13 | 1729ba0461c |
14 | a534d63511 |
15 | 589775cec6 |
hex | 31e7d6ac4b |
214343003211 has 4 divisors (see below), whose sum is σ = 285790670952. Its totient is φ = 142895335472.
The previous prime is 214343003197. The next prime is 214343003213. The reversal of 214343003211 is 112300343412.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 214343003211 - 211 = 214343001163 is a prime.
It is a super-3 number, since 3×2143430032113 (a number of 35 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (214343003213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35723833866 + ... + 35723833871.
It is an arithmetic number, because the mean of its divisors is an integer number (71447667738).
Almost surely, 2214343003211 is an apocalyptic number.
214343003211 is a deficient number, since it is larger than the sum of its proper divisors (71447667741).
214343003211 is an equidigital number, since it uses as much as digits as its factorization.
214343003211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71447667740.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 214343003211 its reverse (112300343412), we get a palindrome (326643346623).
The spelling of 214343003211 in words is "two hundred fourteen billion, three hundred forty-three million, three thousand, two hundred eleven".
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