Base | Representation |
---|---|
bin | 11111001100001110011… |
… | …101010101000001011101 |
3 | 21120220120102001021212002 |
4 | 133030032131111001131 |
5 | 240104221400000023 |
6 | 4320402334252045 |
7 | 310600140004514 |
oct | 37141635250135 |
9 | 7526512037762 |
10 | 2143431250013 |
11 | 75702a074939 |
12 | 2a74b2957025 |
13 | 127180c71101 |
14 | 75a57aa167b |
15 | 3ab5007ab28 |
hex | 1f30e75505d |
2143431250013 has 2 divisors, whose sum is σ = 2143431250014. Its totient is φ = 2143431250012.
The previous prime is 2143431249991. The next prime is 2143431250061. The reversal of 2143431250013 is 3100521343412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2101345958404 + 42085291609 = 1449602^2 + 205147^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2143431250013 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2143431256013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1071715625006 + 1071715625007.
It is an arithmetic number, because the mean of its divisors is an integer number (1071715625007).
Almost surely, 22143431250013 is an apocalyptic number.
It is an amenable number.
2143431250013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2143431250013 is an equidigital number, since it uses as much as digits as its factorization.
2143431250013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 2143431250013 its reverse (3100521343412), we get a palindrome (5243952593425).
The spelling of 2143431250013 in words is "two trillion, one hundred forty-three billion, four hundred thirty-one million, two hundred fifty thousand, thirteen".
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